Shiran's Blog

I wanted to get all the computer's names as I was doing a till balancing program, related to a supermarket (POS application). On a report I wanted to filter the daily balance.

Daily balance of all stations and station wise. I thought this might helpful, if I share the code snippet with you.


private List ComputersInNetwork()
{
List computerList= new List();
using (DirectoryEntry root = new DirectoryEntry("WinNT:"))
{
foreach (DirectoryEntry computers in root.Children)
{
foreach (DirectoryEntry computer in computers.Children)
{
if ((computer.Name != "Schema"))
{
computerList.Add(computer.Name);
}
}
}
}
computerList.Add("All");
computerList.Sort();
return list;
}

Happy coding.

This occurs due to not understanding the expected parameter type for the XmlDocument.Load("filename") method. This method expect a file name.

Look at the following example, this throw the above error.

eg:
//getting a soap response
string sXml = nc.CurrencyExchangeRatesForWeb();
XmlDocument doc = new XmlDocument();
doc.Load(sXml);

To avoid this error, we can use XmlDocument.LoadXml("string") method, following example shows the solution,

eg:
string sXml = nc.CurrencyExchangeRatesForWeb();
XmlDocument doc = new XmlDocument();
doc.LoadXml(sXml);

Happy coding

I have seen many young developers are struggle with getting
the only the file name from the full path.

Here is a simple code snippet to get the file name.

string path = "C:\\TEMP\\temp.bmp";
string fileName = System.IO.Path.GetFileName(path);

Happy coding.

We know if we have manually binds the data then, we can access the checkbox or what ever the control by it's id.
as follows

CheckBox ck = (CheckBox)GridView1.Rows[e.NewEditIndex].Cells[8].FindControl("yourCheckBoxControl");

 

What if you auto bided the data to a gridview,

CheckBox ck = (CheckBox)GridView1.Rows[e.NewEditIndex].Cells[8].Controls[0];